Changes

Jump to navigation Jump to search
'''A note on the derivation of demand'''
 
Recall that:
<center>
<math>M=e(p,u)\,</math>,
so that <math>v(e(p,u),p)=u\,</math> when the expenditure function is evaluated at <math>p\,</math> and <math>u\,</math>. 
<math>\frac{d}{dp(v(M,p))} = \frac{dv(M,p)}{dm} \cdot \frac{dM}{dp} + \frac{dv}{dp} = 0,\,</math> where
<math>\frac{dM}{dp} = \frac{de(p,u)}{dp}\,</math>.
 
<math>\therefore q(m,p) = \frac{de(p,u)}{dp} = -\frac{dv/dp}{dv(M,p)/dm}\,</math>
 
<math>\therefore q(m,p) = -\frac{d}{dp(v(p))}\,</math>\\
</center>
<math></math>
Anonymous user

Navigation menu