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:<math>\therefore \frac{\sum_i(p_i - c_i)}{p} = \frac{D(p) N}{p D'(p)}\;</math>
Subbing in <math>\sum_i p_i = p - \alpha\;</math>:
:<math>\frac{p - \underbrace{\alpha - \sum_i c_i}{c}}{p} = \frac{N}{\eta}\;</math>
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