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With regards to <math>A>C</math>, note that if all other workers are working, then <math>C=\frac{1}{N}(1-\exp[-\rho z (N-1)])</math>.
Now, consider that <math>A>C \iff N> \frac{(1-\exp[-\rho z (N-1)])}{1-\exp[-\rho(z-1)]}</math>.
In the above RHS expression, we know that the numerator is smaller than the denominator, so the fraction is less than 1. We know that <math>N>1</math>, so the inequality always holds.
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