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Again <math> V(0)=0 \,</math>.
:<math> \therefore V_2 = x_1^\frac{1}{2} + x_2^\frac{1}{2}\,</math>
Recalling that <math> x_2 = 1 - x_1 \,</math>
:<math> \frac{\partial V_2}{\partial x_1} =0 \implies x_1 = x_2 = \frac{1}{2}\,</math>
