Changes

Jump to navigation Jump to search
Case 1: <math>z \le y: \quad r_x=\alpha (x-y)</math> obtained by noting that <math>x \ge y</math> and that both of the absolute values are positive and rearranging.
Case 2: <math>y \le z \le x: \quad r_x= 2 \alpha \left (\frac{x+y}{2} + z \right )</math> obtained by noting that the lhs LHS absolute value in equation (1) is positive, whereas the lhs RHS value is negative.
Case 3: <math>x \le z: \quad r_x=-\alpha (x-y)</math> obtained by noting that both of the absolute values are negative and rearranging.
Anonymous user

Navigation menu